MATHEMATICAL LITERACY
PAPER 1
GRADE 12 
NSC PAST PAPERS AND MEMOS
FEBRUARY/MARCH 2018 

SYMBOL

EXPLANATION

M

Method

MA

Method with accuracy

CA

Consistent accuracy

A

Accuracy

C

Conversion

S

Simplification

RT/RG

Reading from a table/graph/diagram

SF

Correct substitution in a formula

O

Opinion/Example/Definition/Explanation

P

Penalty, e.g. for no units, incorrect rounding off, etc.

R

Rounding off

NPR

No penalty rounding or omitting units

AO

Answer only, full marks

 MEMORANDUM 

Question 1 [30Marks] AO

Ques

Solution

Explanation

Topic/L

1.1.1

3½   years ✔✔ A
OR
Three and half a years✔✔A
OR
3,5 years ✔✔A

 2A numerical period
OR
2A period in words
3 years 6 months
(only 1 mark)

 

 

(2)

M
L1

1.1.2

Total Repayment Cost = R1 078,26 × 42 ✔ M/A
= 45 286,92 üCA

 1MA multiply term by instalment
1CA Total cost From Q1.1.1.

 

(2)

F
L1

1.1.3

                           ✔M
Discount = R29 999,00 × 15%
= R4 499,85✔A

1M calc. discount
1A saving

(2)

F
L1

1.2.1

AD : CB = 10,9 : 9,45 ✔M
= 218 : 189 ✔CA

 1M ratio form
1CA simplified form Accept unit ratio

(1: 0,87) OR (1,15 : 1)

(2)

 MP
L1

1.2.2

                                                        ✔M/A
CD = 125,92m – (57,5 + 10,9 + 9,45)
= 48,07m ✔CA

 1M/A subtracting all lengths
1CA length

(2)

 M
L1

1.2.3

Radius = 4,73 m ✔ M
                  2
= 2,365 m ✔A

1M dividing by 2
1A simplification NPR

(2)

M
L1

1.2.4

                           ✔M/A
Total Cost = R97,56/m × 57,5m
= R5 609,70 ✔CA

1M/A multiply cost by correct distance
1CA simplification

(2)

F
L1

1.3.1

 C ✔✔A

 2A city

(2)

 D
L1

1.3.2

Range = 8oC – (– 7oC)✔MA
= 15oC  ✔CA

1MA subtracting correct values
1CA temperature

(2)

D
L1

Ques

Solution

Explanation

Topic/L

1.3.3 (a)

B ✔✔A

2A city

(2)

 P
L1

1.3.3 (b)

Likely OR less likely ✔✔A

2A correct words

(2)

P
L1

1.4.1

Bar graph ✔✔A
OR
Single bar graph.      ✔✔A
OR
Vertical bar graph    ✔✔A
OR
Column graph    ✔✔A

2A correct type

(2)

D
L1

1.4.2

                                                       ✔✔A
Three hundred and sixty one thousand nine hundredand forty eight.

2A number in words

(2)

M
L1

1.4.3

 Q 5  ✔✔A

2A correct question

(2)

D
L1

1.4.4

Average time per mark = 180 min          ✔MA
                                         150
= 1,2 min ✔CA
OR
Average time per mark = 3 hours    ✔MA
                                           150
= 0,02 × 60 min
= 1,2 min    ✔CA
OR
150 marks : 180 min ✔MA
1mark : 1,2 min                              ✔CA

1MA numerator and denominator
1CA simplification
OR
1MA numerator anddenominator
1CA simplification
OR
1MA correct ratio
1CA simplification

 
(2)

D
L1

         
     

[30]

Question 2 [44 Marks]

Ques

Solution

Explanation

Topic/L

2.1.1

Stop order: an instruction to an employer or bank to pay / divert monthly or transfer regularly a certain amount to a person or an account. ✔✔O
OR
Stop order: an instruction that an employee (individual) issue to the employer (bank) to make a series of future dated regular deductions  ✔✔ O
OR
Stop order: Future dated regular monthly deductions ✔✔ O

2O explanation         (2)

F
L1

2.1.2

                                 ✔ M/A
Difference = R940 465,89 – R536 523,25
= R403 942,64 ✔ C/A

1M/A subtraction of correct value
1CA simplification AO      (2)

F
L1

2.1.3 

Number of years (2017 – 2029) = 12    ✔ M/A
Number of months in 12 years = 12 × 12
                                                   = 144 ✔ C              ✔A
Number of months from 10 May to 1 November = 6
Total number of contributions = 144 + 6
= 150    ✔ CA

1M/A calculating years
1C converting years to months
1A additional months
1CA total number of months.
AO (4)

F
L2

2.1.4

 Total contribution value
M/A
= (5 × 12) × R740,22 ✔ RT
= R44 413,20 ✔CA

1M/A multiplying (5 and 12)
1RT reading monthly contribution
1CA total contribution
AO
NPR (3)

F
L2

2.1.5

                                                                                    ✔✔A
a greater / an increased/ a higher / more/ bigger/ larger/ inflated / better

 2A correct missing words (2)

F
L1

Related Items

Ques

Solution

Explanation

Topic/L

2.1.6

                      ✔MA
R740,22 + R740,22 × 8,5%
= R740,22 + R62,9187    ✔M
= R803,14
OR
                ✔M
R740,22 × 108,5% ✔MA
= R803,14
OR
740,22 × 8,5% = 62,9187 ✔MA
∴ 803,14 − 62,9187 = 740,22 ✔M

1MA percentage
1M adding two values
OR
1M multiplying
1MA 108,5%
OR
1MA percentage
1M subtracting values  (2)

F
L1

2.2.1

Hourly overtime rate = R17,76 ×11/3 ✔MA
= R23,68 ✔CA

1MA hours
1CA rate
AO (2)

F
L1

2.2.2

                                                         ✔MA          ✔A
2017 Sunday wage rate = 19,39 × 150% = R29,09
                                ✔A 
Total wage = 3 × 9 × R29,09 ✔M
= R785,43 ✔CA
OR
                                                         ✔MA            ✔A
2016 Sunday wage rate = R17,90 × 150% = R26.85
                                ✔A
Total wage = 3 × 9 × R26,85 ✔M
= R724,95 ✔CA

1MA increasing by 150%
1A Sunday hourly rate
1A hours per day
1M multiplying
1CA wage
AO
1MA increasing by 150%
1ASunday hourly rate
1A hours per day
1M multiplying
1CA wage
NPR (5)

F
L2

Ques

Solution

Explanation

Topic/L

2.2.3 (a)

                                          ✔A

% increase = 17,76 -16,40 × 100%  ✔M
                           16,40
= 8,29268….%
≈ 8,3%
OR
                                    ✔A
% increase = 19,39 -17,90 × 100%    ✔M 
                           17,90
= 8,324…%
≈ 8,3%
OR
                    ✔A
R16,40 × 1,083 = R17,76    ✔M
OR
                    ✔A
R17,90× 1,083 = R19,39    ✔M
OR
                   ✔A
R17,76 ÷ 1,083 = R16,40    ✔M
OR
                      ✔A
R19,39 ÷ 1,083 = R17,90    ✔M

1M percentage
1A correct values used
OR
1M percentage
1A correct values used
OR
1M percentage
1A correct values used
OR
1M percentage
1A correct values used
OR
1M percentage
1A correct values used
OR
1M percentage
1A correct values used (2)

F
L1

2.2.3 (b)

A × 108,3% = 21,93    ✔RT
A =    21,93    ✔M
      108,3%
= R20,25 ✔CA
OR
            ✔ RT
A = 21,93
      1,083 ✔M
= R20,25 ✔CA

 1RT reading values
1M dividing by 108,3%
1CA amount
OR
1RT reading values
1M dividing by 108,3%
1CA amount
AO (3)

F
L2

Ques

Solution

Explanation

Topic/L

2.2.4

2017
Total Weekly Wage  ✔MA      ✔RT
= (6 × 9 × R17,76) + (9 × 150% × R17,76)
= R959,04 + R239,76
= R1 198,80 ✔CA
OR
2016
Total weekly wage
✔MA            ✔RT
= (6 × 9 ×R16,40) + (9 × 150% × R16,40)
=R1 107,00 ✔CA

1RT reading value from the table
1MA multiply with no. of days and hours
1CA    simplification
OR
1RT reading value from the table
1MA multiply with no. of days and hours
1CA    simplification (3)

F
L2

2.3

 Total Income for the day
= 7 × R70 + 35 × R50 + 4 × R75  ✔✔RT ✔M
= R490 + R1 750 + R300
= R2 540    ✔CA
OR
Income from bakkies = 7 × R70 = R490 ✔A
Income from Cars = 35 × R50 = R1 750 ✔A
Income from minibus = 4 × R75 = R300 ✔A
Total Income = R2 540 ✔CA

 2RT correct values
1M multiply price by vehicle type
1CA total income
OR
1A bakkies
1A cars
1A minibus
1CA total income
AO (4)

F
L1

Ques

Solution

Explanation

Topic/L

2.4.1

Employer provides people job/work for pay
OR
                   ✔✔
O
Employer is the company/individual who offers work opportunities for pay. ✔✔O
OR
Employer owner of the company ✔✔O

2O explanation  (2)

F
L1

2.4.2

✔O                    ✔O
Get a few months reduced income after termination of work.
OR                            ✔O
To give employee a short-term financial relief should he/she become unemployed. ✔O
O                              OR                     ✔O
Make provision for some income when a person becomes unemployed or retrenched or retired from work.

2O reason (2)

F
L1

2.4.3(a)

 

RT                              ✔M
B = R6 272,16 – (R1 184,40 + R350,88)
= R4 736,88üCA                          ✔M                         
OR
B = 9 × 6 × 4 ×  21,93    ✔RT
= R4 736,88✔CA

1RT amounts
1M subtracting
1CA value of B
OR
1RT amounts
1M multiplying all values
1CA value of B Accept B = (R5 131,62 If 26 days used) (3)

 

F
L1

2.4.3 (b)

1% of gross salary = R6 272,16 – R6 209,44 ✔MA
= R62,72 ✔A
Total UIF amount = 2 × R62,72
= R125,44 ✔CA
OR
                            ✔A
Total UIF amount = 2 × (1% of R6 272,16)
= 2 × R62,7216 ✔MA
= R125,44 ✔CA
OR
Total UIF amount = 2% of R6 272,16    ✔✔ MA
= R125,44      ✔CA

1MA subtracting correct values
1A simplification
1CA total amount payable
OR
1A calculating 1%
1MA 2 contributions
1CA amount
OR
2MA Calculating 2% of salary
1CA amount
AO (3)


L2

     

[44]

QUESTION 3 [25 MARKS]

Ques

Solution

Explanation

Topic/L

 

3.1.1

✔RT            ✔RT                              ✔RT      ✔RT
6 months to 2 years.            OR ( ½ year to 2 years) OR
6 months to 24 months
RT            ✔RT

2RT age
Accept 23-24 months (2)

M
L1

3.1.2

8 kg ✔✔RT

2RT mass/weight (2)


L1

3.1.3

12 months to 15 months ✔✔ RT

2RT (one age in this range) (2)

M
 L1

3.1.4

February ✔✔A

2Acorrect month (2)

M
 L1

3.1.5

BMI = weight (in kg)
          (height in m)2
19,5 kg/m2 =         11,2        ✔ SF
                    (height in m)2
M       
Height = √11,2  M
                 19,5    
= 0,758 m CA

1SF correct values
1M new subject
1M finding sq. root
1CA simplification
AO  (4)

M
L2

3.2.1

Distance = 55 litre × 100 km MA
                  7,6 litre MA
= 723,68
≈ 724 km R

1MA multiply by 100
1MA divide by 7,6
1R distance
AO (3)

M

L2

3.2.2

                          ✔ SF

Average speed = 189     =    189
                            01h45      1,75 C
= 108 km/h CA

1C to hours
1SF correct values
1CA Average speed
AO (3)


L2

3.3.1

                                         ✔ SF
Volume = 53,34cm × 17, 78cm × 42,32 cm
= 40 135,66 cm3 ✔ CA
= 40 135,66 litres
    1000   ✔ MA
= 40 litres ✔R

1SF correct substitution
1CA volume
1MA dividing by 1 000
1R volume in litres  (4)

M
L3

3.3.2

P(U)=         12 ✔ A
        12    or 48  A
= 0,25 CA

1A numerator
1A denominator
1CA decimal
AO (3)

P
L2

     

[25]

QUESTION 4 [19 MARKS]

Ques

Solution

Explanation

Topic/L

 

4.1.1

A      A
N10 and N2

1A N10
1A N2

(2) 

MP
L1

4.1.2

                 ✔ RT
Mountain Zebra N.P

2RTcorrect name

(2)

MP
L1

4.1.3

Kirkwood A

2A correct hometown

(2)

MP
L2

4.1.4

                                                    ✔RT            M
Distance = 25 km + (207 km – 22 km ) + 24 km  = 234 km CA
OR
                              RT                    M
Distance = 24 km + ( 380 km – 195 km ) + 25 km = 234 km CA

1RT correct distances

1M adding
1CA difference
OR
1RT correct distances
1M adding
1CA difference
AO 

 (3)  MP
L2

4.2.1

 3750 mm   A
Total exterior length of western wall

2A distance

(2)

MP
L1

4.2.2

= 3 550 mm + 3750 mmA
= 7 300 mm
= 7,3 m C
OR
Total exterior length of western wall
= 3, 55 m + 1, 7 m + 2, 05 m A
= 7, 3 m C

1A adding 3 correct distances
1C conversion to m
OR
1A adding correct distances of Eastern wall (opp. Side //)
1C conversion to m
AO                                      

(2)

MP
L1

4.2.3

Living room. A

2A
(Passage and/or Kitchen maximum 1 mark)

(2)

MP
L1

4.2.4

Bedroom 2 A

2A room

(2)

MP
L1

4.2.5

Wash basin/sink/water basin OR Shower    A
OR
Cupboard

2A any item

(2)

MP
L1

     

[19]

QUESTION 5 [32MARKS]

Ques

Solution

Explanation

Topic/L

5.1.1

Numerical A

2A answer

(2)

D
L1

5.1.2

50%  A

2A answer

(2)

D
L1

5.1.3

Range = Maximum - minimum M
34 = 90 – F RT
F = 90 – 34
= 56 🗸CA

1M range concept (can be implied)
1RT correct values
1CA simplification
AO

 

(3)

D
L2

5.1.4

Median % = 67 + 69 🗸M
                         2
=     68 🗸A

1M concept of median
1A median
AO

(2)

D
L2

5.1.5

Inter-quartile range = Q3 - Q1M
Inter-quartile range = 70 – 20 RT
= 50 🗸 CA

1M IQR concept(implied)
1RT correct values
1CA simplification
AO

(3)

D
L2

5.1.6

66 🗸🗸A

2A mode

(2)

D
L1

5.1.7

Mean =        sum of the marks        
               totalnumber of learners
                 🗸A
70 = 1741 + H     🗸MA
              26
1 820 = 1 741 + H H = 79 🗸CA

  1MA mean concept (implied)
1A adding values

1CA value of H
AO

 (3)

D
L3

5.1.8

P (equal marks) = 13 🗸A
                             26 🗸 A
= 1
   2    🗸CA

1A numerator
1A denominator
1CA simplification
AO

(3)

P
L3

Ques

Solution

Explanation

Topic/L

5.2.1

                                                                             🗸MA
Q = 288 912 + 393 954 + 94 552 + 192 933 + 650 033 + 299 994 + 575 371 + 312 273 + 372 090 = 3 180 118 🗸CA
OR
                                   🗸MA  
Q = 15 353 036 – 12 172 919 = 3180 118 🗸CA

1MA adding all Non- literate adults
1CA Simplification
OR
1MA subtracting Literate from Total
1CA simplification 
AO (2)

D

L1

5.2.2

                                         🗸 RT
% literate = 12172 919 × 100 🗸M
                   15 353 036
 ≈ 79,3   🗸 CA
OR                                      🗸 RT
% literate = 100 - ( 3 180 118     ×   100)     🗸M
                             15 353 036
≈ 100 - 20,71
≈ 79,3 🗸 CA

1RT numerator and denominator
1M multiply by 100

1CA answer
AO
1RT numerator and denominator
1M multiply by 100
1CA answer
NPR                              (3)

D
L2

5.2.3

 Non Literate: Literacy
= 650 033:1 956 497🗸 RT
= 650 033 : 1956 497       🗸MA
    650 033   650 033
= 1 : 3,009842577
≈1 : 3 or 1 : 3,01 or 1 : 3,0099    🗸 CA

1RT both values
1MA ratio in correct order
CA unit ratio NPR (3)

D
L2

5.2.4

                                               🗸🗸MA

244 282; 609 029; 760 029;784 347; 922 171; 1 120 567; 1 762 494; 1 956 497; 4 013 463

 2MA arranging    (2)
(Descending 1 Mark; Omitting 1 value 1 mark)

 D
L1

5.2.5

Northern Cape (NC) 🗸🗸A

2A correct province  (2)

D
L1

     

[32]

   

TOTAL:

150

Last modified on Wednesday, 11 August 2021 13:42