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GRADE 12 MATHEMATICAL LITERATURE PAPER 2 ERRATA - NSC PAST PAPERS AND MEMOS SEPTEMBER 2016

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MATHEMATICAL LITERATURE
PAPER 2 
ERRATA
NATIONAL SENIOR CERTIFICATE 
SEPTEMBER 2016

ERRATA

TO:DCES: EXAMINATIONS (ALL DISTRICTS) PRINCIPALS: SCHOOLS OFFERING MATHEMATICAL LITERACY 
FROM:CES: ASSESSMENT AND EXAMINATIONS MS N. MBELEKI
SUBJECT:ERRATA: MARKING MEMORANDUM FOR MATHEMATICAL LITERACY P2
DATE:20 SEPTEMBER 2016

  1. This is to inform all institutions offering Mathematical Literacy P2 in Grade 12 for the 2016 Trial Examination that an error in the reproduction of the paper occurred in QUESTION 3.1.
  2. Due to this omission, learners were unable to calculate the answer in QUESTION 3.1.2.
  3. The mark allocation for this question (3.1.2) totals 3 marks.
  4. Please amend the marking memorandum and total mark allocation as follows:

a. QUESTION 3.1.1

3.1  3.1.1

Annual income =368 450 Tax bracket from table=284 101 - 393 200 ✓ RT
Tax = 59 314 +31% of the amount above
= 284 100

= 59 314 +0,31(368 450-284 100)

= 59 314 +0,31 x 84 350✓ S
✓ M ✓M = 59 314 +26 148,50 - [(270 * 2) + 181 x 12]

= 85 462,50 - 8652

= R 76 810,50
       12 ✓ M
-R6 400,88

Monthly = 368 450 ÷ 12
= R30 704, 17/✓ M
% = 6 400,28 x 100
       30 704,17
= 20,85 ✓ CA
Accept 20,9% 

1RT Correct tax bracket
1SF 

1S
1M Multiplying by
12 M
1M Subtracting medical aid credits 1M dividing by 12 1M Monthly Income

1% CA (8)

  L4


B. QUESTION 3.1.2:

  • All learners could not answer this question.
  • Recommendation:
  • Deduct the 3 marks from the total (150) and calculate the final mark out of 147. Convert the 147 back to 150 and proceed as normal.
  • If a candidate scored 75 out of 150, the final mark will be calculated as follows:
    75/147 x 150/1 = 77,5 (rounded off to 78)

 C. QUESTION 5.1.2

5.1  5.1.2 

Front doors = 2 700 ÷ 397
= 6 doors M

= 1 830 ÷ 716
= 2 doors ✓CA

No. of doors = 6 x 2
= 12 doors in 1 board ✓CA

Doors needed = 20

2 boards needed ✓ A

Sides = 2700 ÷ 540
= 5 ✓M

1 830 ÷ 720 = 2

No. of sides = 5 x 2 = 10 Boards needed 2 ✓CA

Back = 2 200 ÷ 720 = 3

1 200 ÷ 800 = 1
3 in 1 board ✓M
∴ For 10 backs = 4 boards ✓CA

Bottom = 2 700 ÷ 540
= 5

1830 ÷ 716 = 2

5 x 2 = 10

No. of boards = 2 ✓CA

Top = 3 400 ÷ 780 = 4

For ten cupboards = 3 tops ✓M

1M Number of doors - length 1M Number of doors - width 1CA Total doors
1A Number of boards
1M Number of sides 

1CA Boards needed for sides

1M Calculating the backs 1CA Number of boards

1CA Number of boards

1M Number of tops
(10) 

 L3


We apologise for any inconvenience caused.
Yours in Quality Education
CES: ASSESSMENT AND EXAMINATIONS N. MBELEKI

Last modified on Friday, 11 June 2021 08:51
Published in Grade 12 Exam Papers and Memos 2016 September

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