MATHEMATICAL LITERACY PAPER 2
GRADE 12
NATIONAL SENIOR CERTIFICATE EXAMINATIONS
MEMORANDUM
MAY/JUNE2021

NOTE:

• If a candidate answers a question TWICE, mark only the FIRST attempt.
• If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution mark the crossed out (cancelled) version.
• Consistent accuracy (CA) applies in ALL aspects of the marking guidelines, however it stops at the second calculation error.
• No CA mark follows after a breakdown.
• If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented.
• General principal of marking, if the candidate makes one mistake he loses one mark.

QUESTION 1 [37 MARKS]
1.1.1 Number of tins = 12 × 10 = 120
No of tins each member gets
= 120 ÷15
= 8
1MA multiplying by 10
1MA dividing by 15
1CA simplification AO
(3)

1.1.2 12,5 kg × 15 = 187,5 kg
5 kg × 30 = 150 kg
0,125 kg × 48 × 15 = 90 kg
10 kg × 15 = 150 kg
12×0,4 kg × 10 = 48 kg
6 × 15 kg = 90 kg
10×0,05 kg ×15 = 7,5 kg
Total = 723 kg
Half ton = 500 kg
Not valid cannot fit into a half-ton bakkie.
1M multiplying by quantity
1C conversion g to kg
1M adding all values
1C conversion ℓ to kg
1CA simplification
1A half ton value
1Oconclusion

OR
12,5 kg × 15 = 187,5 kg
5 kg × 30 = 150 kg
10 kg × 15 = 150 kg
6 × 15kg = 90 kg
Total Weight = 577,5 kg
125 g × 48 × 15 = 90 000 g
400 g × 12 × 10 = 48 000 g
50 g × 10 × 15 = 7 500 g
Total Weight = 145 500 g
= 145,5 kg
Total = 577,5 kg + 145,5 kg
= 723 kg
Half Ton = 500 kg
NotValid.
1M multiplying by quantity
1C conversion ℓ to kg
1C conversion g to kg
1M adding all values
1CA simplification
1A half ton value
1O conclusion(7)

1.1.3 Total costof items where VAT must be added
= R1274,85+ R689,70+ R4 154,85+ R1499,85
= R7 619,25
VAT amount = R7 619,25 × 15%
= R1 142,89
Total amount
= R7 619,25 + R1 142,89 + R1679,85
+ R 1 559,50 + R1049,85
= R13 051,34
Wholesaler A
1MA adding items that are subject to VAT
1A simplification
1MCA multiplying by 15%
1A simplification
1MCA adding all values
1CA simplification
1A choosing wholesale A

OR
Total costof items where VAT must be added
= R1274,85+ R689,70+ R4 154,85+ R1499,85
= R7 619,25
R7 619,25 × 1,15 = R8 762,14
R8 762 + R1 679,85 + R1 559,50 + R1 049,85
= R13 051,34
Wholesaler A
1MA adding items that are subject to VAT
1A simplification
2MA multiplying by 115%
1MCA adding all values
1CA simplification
1A conclusion

OR
Total cost of items
= R1 679,85 + R689,70 + R4 154,85 + R1 274,85 + R1 559,50 + R1 049,85 + R 1 499,85
= R11 908,45
Excluding VAT exempted items
= R11 908,45 – R4 289,20
= R7 619,25
VAT amount = R7 619,25 × 15%
= R1 142,89
Total amount = R 11908,45 + R1142,89
= R13 051,34
Wholesaler A
1A simplification
1MA subtracting items that have VAT
1A simplification
1MA multiplying by 15%
1A simplification
1CA simplification
1A conclusion

OR
Items that attract VAT:
Without VAT + 15% VAT = Including VAT
R1 274,85 + R191,23 = R1 466,08
R689,70 + R103,46 = R 793,16
R4 154,85 + R623,23 = R4 778,08
R1 499,85 +R244,98 = R1 724,83
R7 619,25 + R1 142,89 = R8 762,14
VAT exempted items
= R1 679,85 + R1 559,50 + R1 049,85
= R4 289,20
Total including VAT
= R8 762,14 + R4 289,20
= R13 051,34
Wholesaler A
1MA multiplying by 15%
1A simplification
1CA simplification
1A simplification
1MCA adding all values
1CA simplification
1A conclusion
(7)

1.1.4 2020 price = R659,70
2021 price = R659,70 × 105,17%
= R693,80649
2022 price = R693,80649 × 105,3%
= R730,57823..
= R730,58
1RT price
1M multiplying by 105,17%
1S simplification
1MCA increasing with 5,3%
1CA simplification

OR
2020 price = R659,70
2021 increase = R659,70 × 5,17%
= R34,10649
2021 price = R659,70 + R34,10649
= R693,80649
2022 increase = R693,80649 × 5,3%
= R36,77714397
2022 price = R693,80649 + R36,77714397
≈ R730,58
1RT price
1M adding 5,17%
1S simplification
1M increasing with 5,3%
1CA simplification

OR
R659,30 × 1,0517 × 1,053 = R730,58
1RT price
1M multiplying by 105,17%
1MCA increasing with 5,3%
2CA simplification

OR
2020 Unit price
= R 659 70 = R21,99
       30
2021 price = R21,99× 105,17%
= R23,126883
2022 price /prys = R23,126883 × 105,3%
= R24,3526…
= R24,35
or
R24, 352607799 × 30 = R730, 58
1RT price
1M multiplying by 105,17%
1S simplification
1MCA increasing with 5,3%
1CA simplification
(5)

1.2.1

1. Outer diameter = 73 mm
   = 7,3 cm
   Circumference of a circle
   = 7,3 × 3,142
   = 22,9366 cm
   Surface area of the label 
   = circumference × height
   = 22,9366 cm × 10,6 cm
   = 243,12796 cm²
   OR
   Surface area = 7,3 × 3,142 × 10,6
   = 243,12796 cm² 
   1C conversion
   1SF substitution
   1MCA multiply with 10,6
   1CA simplification
   OR
   Surface area = 73 × 3,142 × 106
   = 24312, 796 mm²
   = 243,12796.. cm²
   1SF substitution
   1MA multiply with 106
   1CA simplification
   1C conversion
   (4)
2. Total length = circumference + overlap
   = 22,9366 cm + 0,6 cm
   = 23,5366 cm
   CA from 1.2.1 (a)
   1MCA adding to circumference
   1CA simplification
   (2)

1.2.2 Number of packs lengthwise /Getal pakke in lengte
= 117 
   29,2
≈ 4
Number of packs width-wise/Getal pakke in breedte
= 66 
 21,9
≈ 3
Number of layers of packs height-wise/Getal lae
= 50 
 10,8
= 4,63
≈ 4
The first layer will have 
No packs 4×3 = 12
cans in a pack = 12 × 12
=144 cans
Number of cans in a crate
= 144 × 4
= 576
Mass = 576 × 440 g or 576 × 400 g
= 253 440 g = 230 400
= 253,44 kg = 230,4 kg
Mass of the crate
= 280 kg – 253,44 kg or 280kg – 230,4
= 26,56 kg = 49,6 kg
Not valid
1MA dividing 29,2
1Rround down
1CA simplification
1CA simplification
1CA simplification
1CA number of cans
1CA mass of the shipment
1MCA crate mass
1O conclusion

OR
Number of packs lengthwise
=117
 29,2
≈ 4
Number of packs width-wise
= 66 
 21,9
≈ 3
Number of layers of packs height-wise
= 50 
 10,8
= 4,63≈ 4
Number of packs in a crate
= 4 × 3 × 4 = 48
Number of tins in a crate
= 48 × 12 = 576
Mass = 576 × 440 g or 576 × 400 g
= 253 440 g = 230 400
= 253,44 kg = 230,4 kg
Mass of the crate
= 280 kg – 253,44 kg or 280kg – 230,4kg
= 26,56 kg = 49,6 kg
Not valid/ Nie geldig nie
1MA dividing 29,2
1S round down
1CA simplification
1CA simplification
1CA simplification
1CA number of cans
1CA mass of the shipment
1MCA crate mass
1O conclusion
(9)
[37]

QUESTION 2 [41 MARKS]
2.1.1 South East or SE
2A correct direction
(2)

2.1.2 Distance= 6,8 km – (0,19 + 3,2 + 2,1) km
= 1,31 km
1RT all correct values
1M subtracting from 6,8 km
1CA simplification
(3)

2.1.3 Fort Street
2A correct street
(2)

2.1.4 12 min = ¹²/₆₀ hour = 0,2 hour
Distance = Speed × time
6,8 km = speed × 12 min
Speed =  6,8 km  = 34 km/h
              0,2 hour
1C convert min to hour
1SF substitution
1S changing subject of the formula
1CA simplification
(4)

2.1.5 Distance = Speed × time
= 36,5 km/h × ¹¹/₆₀
= 6,69166667 km
Difference = 6,8 km – 6,69 km
= 0,1083333 km
≈ 108,3 m
1SF correct values
1A distance
CA simplification
NPR if answer is in metre
(3)

2.2.1 Length = (26 + ¹⁰/₁₂) feet = 26,83333... feet
Area = 26,8333... × 4 feet
= 107,333… feet2
LESS THAN
1M adding
1C conversion
1CA simplification
1SF substitution
1CA simplification
1O conclusion

OR
Area = 26 feet 10 inches × 4 feet
= 104 feet 40 inches
40 inches/duim = ⁴⁰/₁₂
= 3 feet 4 inches
Total area = 104 feet + 3 feet 4 inches
= 107 feet 4 inches
LESS THAN 
1SF substitution
1CA simplification
1C conversion
1M adding
1CA simplification
1Oconclusion

OR
L = 26 × 12 + 10 = 322 in
W = 4 × 12 = 48 in/dm
Area = 322 × 48
= 15 456 in²
= 15 456
      12²
= 107,733 feet2
LESS THAN 
1M adding
1CA simplification
1C conversion
1SF substitution
1CA simplification
1O conclusion

OR
L = 26 × 12 + 10 = 322 in
W = 4 × 12 = 48 in/dm
Area = 322 × 48
= 15 456 in²
109 feet2 × 122 = 15 696 in²
Area = 15 456 in² which is LESS THAN/Minder as
1M adding
1CA simplification
1C conversion
1SF substitution
1CA simplification
1O conclusion
(6)

2.2.2 Measured distance = 82 mm = 8,2 cm
Scale :8,2 cm : 25 feet
1 cm : 25 
          8,2
1 cm: 3,05 feet
[Accept distances from 8cm to 8,6 cm]
1A measurement
1 M scale
1CA simplification
(3)

2.2.3 Rate per square foot /koers per vierkante voet
= 2 188,71
    1 045
= C$ 2,09445...
≈ C$ 2,09 / foot²
1RT correct values
M dividing by 1 045
1CA simplification
NPR
(3)

2.3.1 Annual rent =C$ 6000 × 4 = C$24 000
Price to rent ratio/huurprysverhouding
=Average PropertyPrice
   Average Annual Rent
= CS 24 000
  C$ 300 000
= 12,5
Tumi should buy.
1MA calculating annual rent
1SF substitution
1CA simplification
1O conclusion
(4)

OR
Quarterly price=300 000 = 75 000
                              4
Price to rent ratio =75 000 = 12,5
                               6 000
Tumi should buy.
1MA calculating quarterly price
1SF substitution
1CA simplification
1O conclusion
(4)

2.3.2

1. P = ³/₁₂ 
   = ¼
   1RT numerator
   1RT denominator
   1CA simplification
   (3)
2. IQR = Q3 – Q1/IKO = K3 – K1
   14,25 = 17,89 – Q1
   Q1 = 17,89 – 14,25
   = 3,64
   1M IQR formula
   1SF substitution
   1CA simplification
   (3)
3. Minimum: North America is lower than Africa
   Maximum: North America is lower than Africa
   Median North America (7,59) is lower than Africa
   It is better to own/buy a house in North America.
   1A minimum
   1A maximum
   1A median of North America
   1A median
   1O conclusion
   OR
   

   	North America	Africa
   Min	2,11	2,36
   Max	15,26	27,41
   Median	7,59	12,19

   It is better to own/buy a house in North America.
   1A minimum
   1A maximum
   1A median of North America
   1A median
   1O conclusion
   (5)

[41]

QUESTION 3 [32 MARKS]
3.1.1 C = - 16 302 + 15 030 + 577 196 + 297 012 +783 526
= 1 656 462
1MA adding all correct values
1A simplification
AO
(2)

3.1.2 57 ,730 million = 57 730 000
P =   4 917 029  = 0,085
       57 730 000
1C converting to number
1RT numerator
1CA denominator
1CA simplification

OR
P = 4,917029 = 0,085
         57,73
1C taxpayers to millions
1RT numerator
1A denominator
1CA simplification
P for rounding
(4)

3.1.3 Mean = 577 196 000 000  = R202 096,397
                           2 856 043
Monthly mean
= 202 096,397
          12
≈ R16 841,37
1RT correct values
1C conversion
1MA dividing by 2 856 043
1MA dividing by 12
1CA simplification
(5)

3.1.4 Percentage assessed =      16 million      x 100%
                                               356 199 million
= 0,00449 %
Rounded this will be 0,0%
1RT correct values
1M percentage calculation
1CA simplification
1O explanation
(4)

3.2.1 Monthly taxable income
= R26 904,22 × 100 - 7,5
                              100
= R26 904,22 × 92,5%
= R24 886,40
Annual taxable income
= R24 886,40 × 12
= R298 636,80
1MA subtracting 7,5%
1MA calculating %
1A simplification
1CA simplification

OR
Monthly pension payable
= R26 904,22 × 7,5 
                         100
= R2017,82
Monthly taxable income 
= R26 904,22– R2017,82
= R24 886,40 
Annual taxable income
R24 886,40 × 12
= R298 636,80
1MA calculating percentage
1A calculating %
1MA simplification
1CA simplification

OR
Annual gross salary
= R26 904,22 × 12
= R322 850,64
Annual pension payable
= R322 850,64 × 7,5 
                          100
= R24 213,80
Annual taxable income
= R322 850,64 – R24 213,80
= R298 636,84
1A simplification
1MA calculating percentage
1CA calculating %
1CA simplification
(4)

3.2.2 April price without VAT
= R172,50 = R150 
      1,15
VAT in March
= R150 × 14% = R21
March price with VAT
= R150 + R21= R171
1MA dividing by 115%
1CA simplification
1MCA 14 % VAT
1CAsimplification

OR
March Price with VAT
= R172,50 x 1,14
      1,15
= R171
2MA dividing by 115%
1MCA 114 % VAT
1CAsimplification
(4)

3.2.3

1. Gauteng, WCape, KZN , ECape, Mpumalanga,
   Limpopo, NWest, Free State, NCape
   2RT All Correct provinces
   2A correct order
   (4)
2. It is to show that all provinces are different (tax payers’ population/filers and tax due to income),
   or
   Tax collected per province differ due to a number of factors (e.g. tax payers and percentage, tax assessed and percentage; tax payers salary).
   2A reason
   (2)
3. Not valid, percentage of North West is higher than that of Free State but the arrow is shorter.
   Or Free State tax assessed and percentage is lower than that of the North West, however the Free State arrow is taller.
   Or the arrow lengths vary according to the number of tax payers.
   1O not valid
   2O reason
   (3)
   [32]

QUESTION 4 [40 MARKS]
4.1.1 Number of busses
= 250 000
     13,2
= 18 939,39394
≈ 19 000
1MA dividing by 13,2
1A simplification
1R rounding
(3)

4.1.2

1. Exchange rate A: 
   R15,97
   R50 000 000 000
   = 3 130 870382
   Exchange rate B:
   R15,966728
   R50 000 000 000
   = 3 131 511 979 euro
   Difference
   = (3 131 511 979 –3 130 870382) euro
   = 641 597 Euro
   1MA dividing by exchange rate
   1A simplification
   1MA dividing by exchange rate
   1A simplification
   1MCA subtracting
   1CA simplification
   OR
   Exchange rate A: 
   R15,97
   R50 billion
   = 3,130870382 billion
   Exchange rate B: 
   R15,966728
   R50 billion
   = 3,131511979 billion
   Difference
   = (3,131511979 –3,130870382) billion
   = 641 597 Euro
   1MA dividing by exchange rate
   1A simplification
   1MA dividing by exchange rate
   1A simplification
   1MA subtracting
   1CA simplification
   (6)
2. Exchange rate B, it gives a higher value (€641 597 more)/shows more money will be made for the taxis
   OR
   Exchange rate B, it is stronger against the Euro.
   CA FROM 4.1.2(a)
   1O choice
   2O reason
   (3)

4.1.3 Total parts = 4 + 5 + 75 = 84
Using = 15 000 000
⁷⁵/₈₄ x total number of commuters = 15 000 000
Total number of commuters
= 15000000 x ⁸⁴/₇₅ = 16 800 000
Number not using a taxi 
= 16 800 000 – 15 000 000
= 1 800 000
1MA adding
1A simplification
1MA working with ratio
1CA simplification

OR
Train : Bus : Taxi
4 : 5 : 75
Not using a taxi = 4 + 5 = 9
Number not using taxi
=15 000 000 x 9
         75
= 1 800 000
1MAsimplification
1MA working with ratio
1A simplification
1CA simplification

OR
Not using a taxi = 4 + 5 = 9
Using ratio:
9 : 75
n: 15 million
75n = 9 × 15 million
n= 1,8 million or 1 800 000
1MA adding
1A simplification
1MA working with ratio
1CA simplification

OR
Not using a taxi = 4 + 5 = 9
Using ratio : 9 : 75
15 000 000 ÷ 75 = 200 000
200 000 × 9 = 1 800 000
1MA adding
1A simplification
1MA working with ratio
1CA simplification
(4)

4.1.4 Distance to moon and back
= 384 402 × 2
= 768 804 km
Number of trips
= 19 000 000 000
        768 804
= 24 713,71117
Valid, more than 24 000
1MA multiplying with 2
1MA multiplying
2A simplification
1O conclusion

OR
Distance travelled for 24 000 trips to moon and back
= 24 000 × 384 402 km × 2
= 18 451 296 000 km
Taxis travel 19 000 000 000 km
Valid, it will more than 24 000 trips
1MA dividing by 24 000
1A simplification
1MA dividing by 2
1CA simplification
1O conclusion

OR
Kilometres travelled per trip
= 19 000 000 000 ÷ 24 000 = 791 666,6
One way distance
= 791 666,6 ÷ 2 = 395 833 km
It is more than the distance to the moon.
1MA multiplying with 2
1A simplification
1MCA dividing
1CA simplification
1O conclusion

4.2.1 9 Jan 2015 to 9 Jan 2016 – 365 days
9 Jan 2016 to 9 Jan 2017 – 366 days
9 Jan 2017 to 9 Jan 2019 – 730 days
9 Jan 2019 to 3 Jan 2020 – 359 days
Total days
= 365 + 366 + 730 + 359 = 1 820
1A number of days in full year
1A days till 3 Jan (subtracting 6)
1MCA adding 1
1CA simplification

OR
Total days
= 365 × 5 + 1 – 6
= 1 820
1A number of days in full year
1A days till 3 Jan
1MCA adding
1CA simplification
(4)

4.2.2 Share price in cent
= 2063 – 1268
= 795
1MA subtracting converted amount
1CA simplification (2)

4.2.3

1. Percentage change/Persentasie verandering
   = New - old x 100%
          old
   = 2 063 - 2 138 x 100%
            2 138
   = – 3,50795%…
   Correct, it went down by 3,51% rounded to 2 decimal places.
   1RT correct values
   1A simplification
   1M % change calculation
   1CA simplification
   1O conclusion
   OR
   Percentage change
   = 2063 × 100% ≈ 96,49%
       2138
   100% – 96,49% = 3,51%
   Correct, it went down by 3,51%
   1RT correct values
   1SF into the % change formula
   1MA % change calculation
   1CA simplification
   1O conclusion
   OR
   Amount = 2 138c × 3,51%
   = 75 c
   Decrease = 2 138 c – 75 c
   = 2 063 c
   Correct, it went down by 3,51%
   1M % change calculation
   1RT correct values
   1A simplification
   1CA simplification
   1O conclusion
   OR
   Percentage change = 100% – 3,51% = 96,49%
   Share price = 2 138c x 0,9649
   = 2 062,9562 = 2 063c
   It is correct. It was rounded to the nearest cent.
   1RT correct values
   1MA % change calculation from previous balance
   1A simplification
   1CAsimplification
   1O conclusion
   (5)
2. Went down
   2016, 2017, 2019, and 2020
   Hence ⁴/₅ x 100% = 80%
   Statement is correct.
   1O conclusion award with justification
   1O reasoning 4 years going down
   1O verifying the percentage
   OR
   Correct, share prices went down in 2016,
   2017,2019 and 2020 but went up 2018
    ⁴/₅ x 100% = 80%
   1O reasoning 4 years going down
   1O verifying the percentage
   1O conclusion
   (3)

4.2.4 Buying 
= 5 000 × 1 611 = 8 055 000 c = R80 550
Sell
= 5 000 × 2 350 = 11750000 c = R117 500
Profit  = R117 500 – R80 550 = R36 950
1RT correct values
1A difference
1C converting to rand
1MCA multiplying
1CA simplification

OR
Difference in price
= 2 350 – 1 611 c
= 739 c
= R7,39
Profit  = R7,39 × 5 000
= R36 950
1RT correct values
1A buy
1C converting to rand
1CA sell
1CA simplification
(5)
[40]
TOTAL: 150