INSTRUCTIONS TO MARKERS

  1. All questions with multiple answers imply that any relevant, acceptable answer should be considered.
  2. Calculations
    2.1 All calculations must show the formulae.
    2.2 Substitution of values must be done correctly.
    2.3 All answers MUST contain the correct unit to be considered.
    2.4 Alternative methods must be considered, provided that the correct answer is obtained.
    2.5 Where an incorrect answer could be carried over to the next step, the first answer will be deemed incorrect. However, should the incorrect answer be carried over correctly, the marker has to re-calculate the values, using the incorrect answer from the first calculation. If correctly used, the candidate should receive the full marks for subsequent calculations.
    2.6 Markers should consider that candidates’ answers may deviate slightly from the marking a guideline depending on how and where in the calculation rounding off was used.
  3. These marking guidelines are only a guide with model answers.
  4. Alternative interpretations must be considered and marked on merit. However, this principle should be applied consistently throughout the marking session at ALL marking centres.

MEMORANDUM

QUESTION 1: OCCUPATIONAL HEALTH AND SAFETY
1.1 Accident means an incident arising out of and in the course of an employee’s employment and resulting in a personal injury, illness or theΒ death of the employee. (2)
1.2

  • Take reasonable care for the health and safety of him/herself and of other persons who may be affected by his or her action.
  • Cooperate with the employer or persons to enable any duties given by the requirements and procedures.
  • Carry out any lawful order given to him, and obey the health and safety rules and procedures laid down by his employer or by anyone authorised there by his employer, in the interest of health or safety.
  • If any situation which is unsafe or unhealthy comes to his/her attention, as soon as practical report this to his/her employer, or a healthy andΒ safety representative who should report it to the employer. (Any 2) (2)

1.3

  • Horseplay
  • Running in the workshop
  • Throwing things
  • Leaving bags, stools or material in the walkway
  • Spilling a liquid or oil without cleaning.
  • Any relevant answer. (Any 2) (2)

1.4 Third degree burn: where all layers of skin have been burned, causing permanent skin damage affecting fat, muscle and even bone. (2)
1.5

  • To review the effectiveness of health and safety measures.
  • To identify hazards and potential major incidents at the workplace. (2)

[10]

QUESTION 2: RLC CIRCUIT
2.1
2.1.1 The current and the voltage are out of phase with each other andΒ the current is leading the voltage by 90Β°. (2)
2.1.2 The current and the voltage are out of phase with each other andΒ the current is lagging the voltage by 90Β°. (2)
2.1.3 The current and voltage are in phase and their phase angle isΒ zero. (2)
2.2
2.2.1

  • 𝑋𝐿 = 2πœ‹πΉπΏ
    = 2πœ‹ Γ— 60 Γ— 44 Γ— 10βˆ’3
    = 16,587 Ω (3)

2.2.2

  • 𝑋𝑐 =Β  Β  1Β  Β  Β 
    Β  Β  Β  Β  Β 2πœ‹πΉπΆ
    𝑋𝑐 =Β  Β  Β  Β  Β  Β 1Β  Β  Β  Β  Β 
    Β  Β  Β  Β  2πœ‹Γ—60Γ—120
    𝑋𝑐 = 22,105 Ω (3)

2.2.3

  • 𝑍 = βˆšπ‘…2 + (𝑋𝐿 βˆ’ 𝑋𝑐)2
    = √252 + (22,105 βˆ’ 16,58)2
    𝑍 = 25,6 Ω (3)

2.2.4

  • 𝐼𝑇 = 𝑉𝑇
    Β  Β  Β   𝑍𝑇
    = 120
    Β  25,6
    = 4,69 𝐴 (3)

2.3 The capacitive reactance will decrease because the capacitiveΒ reactance is inversely proportional to frequency. (3)
2.4
2.4.1

  • 𝐼𝑇 = βˆšπΌπ‘…2 + (𝐼𝐿 βˆ’ 𝐼𝐢)2
    = √62 + (5 βˆ’ 4)2
    = 6,08 𝐴 (3)

2.4.2

  • πΆπ‘‚π‘†πœƒ = 𝐼𝑅
    Β  Β  Β  Β  Β  Β  𝐼𝑧
    πœƒ = πΆπ‘œπ‘ βˆ’16
    Β  Β  Β  Β  Β  Β  Β  6,08
    = 9,305Β° (3)

2.4.3

  • 𝑋𝐿 = 𝑉𝑇
            𝐼𝐿
    𝑋𝐿 = 240Β 
    Β  Β  Β  Β  Β 5
    𝑋𝐿 = 48 Ω (3)

2.4.4

  • 𝑋𝑐 = 𝑉𝑇
            𝐼𝐢
    𝑋𝐢 = 240
    Β  Β  Β  Β  Β  4
    = 60 Ω (3)

2.5
2.5.1

  • 𝐹𝑅 =Β  Β  1Β  Β  Β 
    Β  Β  Β  Β 2πœ‹βˆšπΏπΆ
    𝐹𝑅 =Β  Β  Β  Β  Β  Β  Β  1Β  Β  Β  Β  Β  Β 
    Β  Β  Β  2πœ‹βˆš0,2Γ—0,05βˆ’6
    𝐹𝑅 = 1 591,5 𝐻𝑧  Β  (3)

2.5.2

  • 𝑋𝐿 = 2πœ‹πΉπΏ
    𝑋𝐿 = 2πœ‹ Γ— 1 591,5 Γ— 0,2
    𝑋𝐿 = 1 999,938 Ω
    𝑄 = 𝑋𝐿
    Β  Β  Β  𝑅
    𝑄 = 1999,938
    Β  Β  Β  Β  Β  Β 10
    𝑄 = 200Β  Β (4)

2.5.3

  • π΅π‘Š = πΉπ‘Ÿ
    Β  Β  Β  Β  Β  𝑄
    π΅π‘Š = 1591,5
    Β  Β  Β  Β  Β  Β  Β 200
    = 7,958 HzΒ  Β  (3)

2.6
2.6.1

  • 𝑄 = πΉπ‘Ÿ
    Β  Β  Β π΅π‘Š
    𝑄 = 95Γ—106
    Β  Β  Β  200Γ—103
    Q = 475 HzΒ  (3)

2.6.2

  • 𝑋𝑐 =Β  Β  Β 1Β  Β Β 
    Β  Β  Β  Β  2πœ‹πΉπΆ
    𝑋𝑐 =Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  1Β  Β  Β  Β  Β  Β  Β Β 
    Β  Β  Β  Β 2πœ‹Γ—95Γ—106Γ—2,5Γ—106
    𝑋𝑐 = 22,105 Ω  (2)

2.6.3

  • 𝑅 = 𝑋𝐿
    Β  Β  Β  𝑄
    𝑅 = 670Β 
    Β  Β  Β  475
    = 1,4466 Ω  Β (2)

[50]

QUESTION 3: THREE-PHASE AC GENERATION
3.1
3.1 aiuhyda
Diagram correctly drawn
VPH
VL
Phasors labelled correctlyΒ  Β Β (4)
3.2.
3.2.1 It is a device that measures the amount of electrical energy consumed over a certain time.Β (2)
3.2.2 A device that measures the power consumed by an application. (1)
3.3

  • Cannot be distributed economically over long distances.
  • Not suitable for heavy duty applications requiring large amounts of power.
  • Uses larger currents and hence thicker cables.
  • For an equivalent application it is not as economical as three-phase.Β (2)

3.4.
3.4.1

  • The current coils of the two wattmeters are connected in series to the red and blue phases.
  • The voltage coils of the two wattmeters are connected to eachΒ other and to the yellow phaseΒ (3)

3.4.2

Related Items

  • PT = W1 + W2
    = 5 000 + 7 500
    = 12 500 W = 12,5 kWΒ Β (3)

3.4.3

3.4.2 auiygduaΒ (5)
3.5
3.5.1

  • V = VL
         √3
    = 380
       √3
    = 219,39 V (3)

3.5.2

  • P = √3VLIL cos ΞΈ
    IL =Β  Β  Β  Β  Β  PΒ  Β  Β Β 
         √3VL cos θ
    =Β  Β  Β  Β 25000Β  Β Β 
    Β   √3Γ—380Γ—0,8
    = 47,48A (3)

3.5.3

  • 𝑄 = √3VLIL sin ΞΈΒ  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β  Β ΞΈ = cosβˆ’1 0,8
    = √3 Γ— 380 Γ— 47,48 Γ— sin(cosβˆ’1 0,8)
    = 18 750,21 VAr = 18,75 kVAr (3)

3.6 Delta is a three-phase, three wire supply and dwellings need a neutralΒ point to supply a single-phase voltage of 220 V. (2)
3.7 A low power factor causes lagging currents. This causes a higher current flow for a given load. As the line current increases, the voltage drop in the conductor increases, which may result in a lower voltage at theΒ equipment. (4)
3.8.1

  • Electricity is generated in power stations by converting natural gases, coal, fossil fuel, nuclear fuel and water action into electrical energy.
  • Basic fuels heat steam to drive turbines which drive hugeΒ generators. (2)

3.8.2

  • The generate electricity is stepped up to a high voltage and then fed to a national grid.
  • From the national grid it is transmitted with overhead power lines to different power stations. (2)

3.8.3

  • Commercial buildings
  • Dwellings
  • Industries
  • Government buildings
  • Any other relevant answer (1)

[40]

QUESTION 4: THREE-PHASE TRANSFORMERS
4.1

  • Core-type
  • Shell-type (2)

4.2 The mineral oil insulates and cools the windings. (2)
4.3

  • Inverse definite minimum time relay
  • Instantaneous overcurrent relay
  • Balanced earth fault relay
  • Buchholtz relay (Any 2)Β (2)

4.4

  • Oil Natural, Air Natural
  • Oil Natural. Air Forced
  • Oil forced, Air Forced
  • Oil Forced, Water Forced (Any 2)Β (2)

4.5 Mutual induction (1)
4.6.
4.6.1

  • S = √3VLSILS
    ILS =Β  Β SΒ  Β Β 
           √3VLS
    =Β  Β 20 000Β Β 
    Β   √3Γ—500
    = 23,09 AΒ (3)

4.6.2

  • VLP = VPHP = 6 000 V
    VPHS = VLS
               √3
    = 500
       √3
    = 288,68 V
    T. Ratio = VPHP
    Β  Β  Β  Β  Β  Β  Β  Β  VPHS
    = 6000
    Β  288,68
    = 20,78 ∢ 1  (6)

4.6.3

  • π‘ƒπΌπ‘π‘ƒπ‘ˆπ‘‡ = 𝑆 cos πœƒ
    = 20 000 Γ— 0,88 OR
    = 17 600 π‘Š = 17,6 π‘˜π‘Š
    OR
    π‘ƒπΌπ‘π‘ƒπ‘ˆπ‘‡ = √3𝑉𝐿𝐼𝐿 cos πœƒ
    = √3 Γ— 500 Γ— 23,09 Γ— 0,88
    = 17596,94 π‘Š = 17,6 π‘˜π‘ŠΒ  Β  Β (3)

4.6.4

  • Ε‹ = π‘ƒπΌπ‘π‘ƒπ‘ˆπ‘‡βˆ’π‘ƒπΏπ‘‚π‘†π‘†πΈπ‘† Γ— 100
    Β  Β  Β  Β  Β  Β  π‘ƒπΌπ‘π‘ƒπ‘ˆπ‘‡
    = 20 000 βˆ’ 160 Γ— 100
    Β  Β  Β  Β  20 000
    = 99,2%Β  Β  Β  Β Β (3)

4.7Β Transformers have no moving parts as a result fewer losses develop, and it delivers a better power output. Transformers have a more efficient design.Β (3)
4.8 A transformer has no moving parts for induction to take place. Unlike DC- current, the AC-current produces an alternating flux which expands and collapses to produce the movement of the magnetic field that is required for induction.Β (3)
[30]

QUESTION 5: THREE-PHASE MOTORS AND STARTERS
5.1 Slip is the difference between the rotor speed and the rotating magnetic field of the stator.Β (2)
5.2

  • To reduce magnetic humming
  • To avoid cogging
  • Increase in effective ratio of transformation between stator and rotor
  • Increase slip for a given torque (Any 2)Β (2)

5.3.
5.3.1 To ensure that the insulation of the windings is not damaged and touching the frame of the motor.Β (2)
5.3.2 Reading must be at least 1 MΩ (1)
5.4 To reduce the starting voltage of the motor windings (1)
5.5.
5.5.1 Three-phase forward reverse starter (1)
5.5.2 They are electrical interlocking contacts that prevent both contactors being energised at the same time.Β (2)
5.5.3 The forward contactor is energised. The N/O F contactor closes, keeping the forward contactor energised after the start forward button is released. At the same time the N/C F opens thus preventing the reverse contactor from being energised until the stop button is pressed.Β (4)
5.5.4 To automatically disconnect the motor from the supply in the event of excessive currents flowing.Β (2)
5.5.5 When the circuit is energised the reverse contactor would be energised and the motor would run in reverse. When the stop button is pressed the motor would run in reverse as soon as the stop button is released. The motor will not be able to run in theΒ forward direction.Β (4)
5.6
5.6 isygfus(6)
5.7

  • VL = VPH = 380 VN
    PINPUT = √3VLIL cos θ
    = √3 Γ— 380 Γ— 25 Γ— 0,866
    = 14 249,58 W = 14,25 kWΒ  Β  Β  (3)

5.8 The velocity of the rotating magnetic field in the stator windings. (2)
5.9

  • Slip = nsβˆ’nr Γ— 100
    Β  Β  Β  Β  Β  Β  ns
    = 1 200 βˆ’1 140 Γ— 100
    Β  Β  Β  Β  Β 1 200
    = 5%Β  Β Β (3)

5.10

  • Supply voltage
  • Frequency
  • Speed
  • Rated current
  • Output power
  • Power factor (Any 2) (3)

5.11 No, the rated frequency and voltage are not suitable for South Africa which uses 380 V / 50 Hz.Β (2)
[40]

QUESTION 6: PROGRAMMABLE LOGIC CONTROLLERS
6.1 6.1.1 D (1)
6.1.2 C (1)
6.1.3 A (1)
6.1.4 E (1)
6.1.5 B (1)
6.2 Software is installed to provide data and instructions to a computer or PLC’s control program, to allow it to interact with its input hardware, to achieve a desired output.Β (3)
6.3
6.3.1
6.3.1 ajgdaΒ (3)
6.3.2
6.3.2 aihyda(3)
6.4 It is a semiconductor device that uses light to transfer an electrical signal between circuits or elements of a circuit while keeping them electrically isolated from each other.Β (3)
6.5

  • Safety or security devices (light beams as a switch for garage door)
  • Control the brightness of screens of electronic devices (TV’s, computers, phones).
  • Switches lights on automatically. (Any 2)Β (2)

6.6 The timer is used to provide an β€˜ON’ or an β€˜OFF’ delay in the operation of a PLC’s logic program.Β (2)
6.7
6.7 iyghuyd(9)

[30]
TOTAL: 200

Last modified on Friday, 25 February 2022 11:53