MATHEMATICAL LITERACY P2
GRADE 12
JUNE 2016
MEMORANDUM
NATIONAL SENIOR CERTIFICATE

Symbol Explanation
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
C Conversion
S Simplification
RT/RG Reading from a table/Reading from a graph
F Choosing the correct formula
SF Substitution in a formula
J Justification
P Penalty, e.g. for no units, incorrect rounding off etc.
R Rounding Off/Reason


QUESTION 1
1.1
1.1.1 Transfer cost ✓✓
Registration of deed of sale ✓✓
Accept any other relevant answer
2A Additional Cost
1.1.2 Amount borrowed = 980 000 ✓x 1,1 ✓
= R 1 078 000 ✓
OR
= 980 000 ✓+ (980 000 x 0,1)✓
= 980 000 + 98 000
= R 1 078 000 ✓
OR
= 0,98 x 1,1
= R 1,078 million
OR
= 0,98 + (0,98 x 0,1)
= 0,98 + 0,098
= R 1,078 million
1M using 980 000
1M using 110%
1CA
PS: If learners use 0,98, penalise with 1 mark if final answer is not in million
1.1.3 It is accessible ✓✓ OR close to shops ✓✓, hospital and schools OR the house has a lot of features ✓✓
Accept any other relevant answer
2A Reason for an ideal place
1.2
1.2.1

  1. Monthly repayment = Bond Amount x Factor
                                           1 000
    = 1 078 ✓x 8,41 ✓
    = R 9 065,98 ✓
  2. Real Cost = 9 065,98 x 30 x 12 ✓✓
    = R 3 263 752,80 ✓
  3. Interest = R 3 263 752,80 - R 1 078 000 ✓
    = R 2 185 752,80 ✓
    CA from 1.1.2
    1M Amount divided by
    1 000
    1RT using correct factor
    1CA
    2MA multiplying with 30 and 12
    1CA
    1M Subtracting
    1CA

1.2.2 Percentage interest = 2 185 752,80 x 100 ✓
                                            3 263 752,80
= 66,97% ✓
Accept 67%
CA from 1.2 1M
1A
1.2.3 At the same interest rate, the longer the loan period, the smaller the factor value which imply that the monthly repayment will be less ✓✓ and the real cost will be higher. ✓✓
Accept any logical explanation
2A Monthly repayments less
2A Real cost more
Learner must refer to both repayments and real cost
1.2.4 At different interest rates, the factor values increase, therefore the monthly repayments ✓✓ will increase as well as the real cost ✓✓
Accept any logical explanation
2A Monthly repayments more
2A Real cost more
Learner must refer to both repayments and real cost
1.3
1.3.1 It means that 90% of the house prices for each of the years shown was lower than the price indicated on that line ✓✓
2A
1.3.2 30% ✓✓
2A
1.3.3 25% ✓✓
2A
1.3.4 Over the various years the house prices remained more or less the same. ✓✓
2A
1.3.5 Price prediction for 2016 = 1 200 000 ✓ x 1,066
= R 1 279 200 ✓
2017 = 1 279 200 x 1,066
= R 1 363 627,20 ✓
OR
2016 = 1 200 000 + (1 200 000 x 0,066)
= 1 200 000 + 79 200
= R 1 279 200
2017 = 1 279 200 + (1 279 200 x 0,066)
= 1 279 200 + 84 427,20
= R 1 363 627,20
1RG Correct value
1CA Price for 2016
1CA Price for 2017
[36]

QUESTION 2
2.1
2.1.1 Length of 1 post = 0,4 m + 8 cm + 1,3 m + 6 cm ✓
= 40 cm + 8cm + 130 cm + 6 cm ✓
= 184 cm ✓
1A Using correct values
1C Conversion
1A Total of values
2.1.2 For the gate to open en close properly without any obstructions.✓✓
2R
2.1.3 Vertical height = Vertical plank – (18 cm x 2) ✓
= 130 cm – 36 cm ✓
= 94 cm ✓
Length of diagonal plank = Vertical height2 + Width of gate2
= 942 + 1262
= 8 836 + 15 876 ✓
= √24712
= 157,200…. cm ✓
= 1,572 m ✓
1SF
1M Subtracting 18 x 2 from the vertical plank
1CA
1SF
1S
1A finding the square root
1CA answer in meters
2.1.4

  • Dig the holes for the posts ✓
  • Plant the poles in the holes ✓
  • Attach the horizontal and diagonal planks with screws ✓
  • Attach the vertical planks to the horizontal and diagonal planks with screws ✓
  • Attach the gate to the posts with hinges ✓
    OR
  • Attach the horizontal and diagonal planks with screws✓
  • Attach the vertical planks to the horizontal and diagonal planks with screws ✓
  • Dig the holes for the posts ✓
  • Plant the poles ✓
  • Attach the gate to the posts with hinges ✓
    5A
    1 mark for each construction
    NB The chronological order is important

2.2
2.2.1

Sakhiswa
High School 
 Minimum R 5000 Maximum R 65 000 
Aphiwe Secondary School  Minimum R 15 000  Maximum R 60 000

Range (Sakhiswa) = 65 000 – 5 000 ✓
= R 60 000 ✓
Range (Aphiwe) = 60 000 – 15 000
= R 45 000 ✓
1RD Correct values (all min & max)
1MA Range
1MA Range
2.2.2 The box-and-whisker plot for Sakhiswa is longer than that of Aphiwe ✓✓
2A
2.2.3 The bottom 75% is much more spread out than the top 25% ✓✓
2A
2.2.4 IQR for Sakhiswa = R 40 000 – R 15 000 ✓
= R 25 000 ✓
IQR for Aphiwe = R 45 000 – R 25 000
= R 20 000 ✓
The IQR for Sakhiswa is greater. ✓✓
OR
The IQR for Aphiwe is smaller.
1M Concept of IQR
1A
1A
2O
2.2.5 Aphiwe Secondary School ✓✓

Related Items

  • The minimum profit is higher ✓✓
    OR
  • The IQR is smaller ✓✓
    OR
  • The bottom 75% profits are higher ✓✓
    OR
  • Range is smaller✓✓
    OR
  • Median is greater ✓✓

2A Correct Choice
2R Reason
[33]


QUESTION 3
3.1
3.1.1

  • It shows a particular route ✓✓
    OR
  • It shows places that you can pass through ✓✓
    OR
  • It gives distances between places ✓✓
    OR
    It shows places where you can stop at ✓✓
    OR
  • It shows the shortest routes ✓✓
    2A

3.1.2 Distance = 480 km – 375 km ✓
= 105 km ✓
OR
Distance = 157 km – 52 km ✓
= 105 km ✓
1RM Correct distances
1A
3.2
3.2.1 Distance to Harare = 532 km + 446 km ✓
= 978 km ✓
Liters used for trip = 7,5 / 100
= 0,075 x 978 km
= 73,35 l ✓
23 February 2016
Cost = 73,35 x 12,15 ✓
= R 891,20 ✓
2 March 2016
Cost = 73,35 x 11,46
= R 840,59 ✓
Difference = R 891,20 - R 840,59
= R 50,61 ✓
She paid less in March, because the petrol price decreased. ✓
1M Adding
1A
1CA Number of litres needed
1RT correct fuel price
1A cost in Rand and cents
1A fuel cost
1CA finding the difference
1O
3.2.2 No ✓

  • Fees for travelling through toll plazas or toll ramps ✓✓
  • Border post fees ✓
    1A
    2A first factor
    1A Second factor

[16]


QUESTION 4
4.1
4.1.1 Percentage population = Males + Female
= 4% + 4% ✓
= 8% ✓
Accept 7,8% - 7,9%
1RD Correct values
1A
4.1.2 France has a narrow base 
which refers to a low birth rate✓
while India has broad base✓
due to a high birth rate✓
1A Description of base for France
1O Reason for base
1A Description of base for India
1O Reason for base
4.2
4.2.1 Measure dimensions:
Length = 6 cm ✓ (accept 5,9 cm – 6,1 cm)
Width = 3,9 cm ✓ (accept 3,8 cm – 4 cm)
Actual length = 6 x 23 ✓
= 138 cm ✓
Actual width = 3,9 x 23
= 89,7 cm ✓
Area = 138 cm x 89,7 cm
= 12 378,60 cm2 ✓
2M Measuring both
Dimensions
1M Using the scale
1CA Length
1CA Width
1CA Area
4.2.2 7 shades of red
7 shades of yellow
P(red and yellow) = 7 + 7
                               35  35
= 14 ✓ x 100%
   35 ✓
= 40% ✓
1A Numerator
1A Denominator
1CA as a %
[15]

TOTAL: 100

Last modified on Tuesday, 15 June 2021 08:08