Thursday, 15 December 2022 07:15

## MATHEMATICS LITERACY PAPER 2 GRADE 12 MEMORANDUM - NSC PAST PAPERS AND MEMOS JUNE 2022

NATIONAL
SENIOR CERTIFICATE
JUNE 2022
MATHEMATICAL LITERACY P2
MARKING GUIDELINE
MARKS: 100

 Symbol Explanation M Method M/A Method with accuracy MCA Method with Consistent Accuracy CA Consistent Accuracy A Accuracy C Conversion S Simplification RT/RG/RM Reading from a table OR Reading from a graph OR Read from map F Choosing the correct formula SF Substitution in a formula J Justification P Penalty, e.g for no units, incorrect rounding off etc R Rounding off OR Reason AO Answer only NPR No penalty for rounding

 QUESTION 1 [20] Ques. Solutions Explanation level 1.1.1 Mozambique ✓✓ 2RT correct country (2) L1Maps 1.1.2 3 ✓✓ 2A no of tented camps (2) L1Maps 1.1.3 9 ✓✓ 2A correct number (2) L1Maps 1.1.4 Main camp ✓✓ 2A type of camp  (2 L1Maps 1.2.1 260 ÷ 10 ✓  26cm 1C dividing by 1 000   1A answer (3) L1Meas. 1.2.2 150 − 40 ✓ 110mm ÷ 1000  0.11m✓ 1MA subtraction 1C dividing by 1000 1A answer (3) L1Meas. 1.2.3 100:150 ✓✓  2:3 ✓ 1RT correct valu4es 1MA ration concept1S simplification L1Meas. 1.3.1 14 × 2 + 3✓ 31✓ 1MA multiplication and addition1A answer (2) L1Meas. 1.3.2 6✓✓ 2A (2) L1Probl [20]

 QUESTION 2 [32] Ques. Solutions Explanations Level 2.1.1 Distance = 1 029 km ✓1 029 x 1 000 ✓1 029 000 m ✓ 1RT correct distance1C conversion1CA answer (3) L2Maps 2.1.2 Cape Town to Johannesburg = 1 402 km ✓Johannesburg to Bloemfontein = 417 km ✓Total = 1 402 + 417         = 1 819 km ✓Cape Town to Nelspruit = 1 779 km ✓Difference = 1 819 – 1 779 = 40 km ✓ Valid ✓ 1RT distance CT to Johannesburg1RT distance to Bloem1CA total distance1RT Nelspruit1CA difference1O valid L4Maps 2.1.3 Distance = 1 393 km ✓Distance = Speed x Time1 393 = 105 x T ✓ T = 1 393/105 ✓ T = 13,2666 hrs = 0,2666 x 60 ✓ = 16 min T = 13hrs 16 min + 2 hrs 30min ✓ = 15hrs 46min ✓ 1RT correct distance1A substitution1S simplification1C hours to minutes1M adding times1CA answer (6) L3Maps 2.2.1 Bar scale ✓ 1A type of scale   (2) L1Maps 2.2.2 Scale 1,2 cm = 5 km ✓            4,3 cm = 5 x 4,3 ✓                        = 21,5   ✓                            1,2                        = 17,916666 x 1 000                        = 1 7 917 m ✓ 1A measuring the scaleAccept 1,1 cm–1,3 cm1A measuring the mapAccept 4,1 cm–4,4 cm1S simplification1CA distance in metres (4) L3Maps 2.2.3 South East ✓✓ 2A direction  (2) L2Maps 2.2.4 2 850 = 870              870       ✓             2 8500,30526 x 100 ✓ 30,526 ✓ = 30,53 cm ✓ 1MA dividing by 2 8501C to cm1CA answer1R rounding to two decimals (4) L2Maps 2.2.5 Fuel consumed:10 km = 1litre 1 km = 1  litre           10litreTherefore 929 km will require: 929 × 1/10 litre ✓M = 929 ÷ 10= 92,9 litre ✓ ACost of return journey = 2 (92,9 × R16,98) ✓ M = 2 (R1 577,442) = R3 154, 884 ✓ S = R3 154, 88 ✓ CA 1M Determine litres1A correct answer1M using 929 km1S simplifyingCA correct answer L2Maps [32] L3Maps

 QUESTION 3 [29] Ques. Solutions Explanations Level 3.1.1 274 +15,25 + 15,25 ✓✓= 304,5 cm ✓OR274 + 2(15,25) ✓274 + 30,5 ✓= 304,5 cm ✓ 1RT all values correct1MA adding overhang1CA answer L1Meas. 3.1.2 274 – 152,5 ✓121,5 x 10 ✓1 215 mm ✓OR(274 x 10) – (152,5 x 10) ✓= 2 740 – 1 525 ✓= 1 215 mm ✓ 1MA subtraction1C to mm1CA answer L2Meas. 3.1.3 10:08 + 1:58 ✓11:66 ✓12:06 ✓ 1MA adding time1S simplification1A correct time L2Meas. 3.1.4 76 + 15,25 ✓= 91,25152,5 – 91,25 ✓= 61,25 ✓ Not valid ✓ 1MA addition1MA subtraction1A answer1O not valid          (4) L4Meas. 3.2.1 100 +40 + 40 + 60 + 20 + 60 + 60 +120+20 +40 ✓✓= 560 cm ✓ 1A all values correct1MA adding all values1A answer (3) L1Meas. 3.2.2 Area = Length x WidthFIGURE 1 = 100 x 40                 = 4 000 cm2 ✓FIGURE 2 = 20 x 60                  = 1 200 cm2 ✓FIGURE 3 = 120 x 40                  = 4 800 cm2 ✓Total area = 4 000 + 1 200 + 4 800 = 10 000 / 10 000 ✓ = 1 m2 ✓ 1A area 11A area 21A area 31MA total area1CA area in square metres L2Meas. 3.2.3 Area to paint = 1 x 2 x 2 ✓ = 4 m2 ✓Litres needed =   4    ✓                           6,2 = 0,645 ✓ = 0,65 m2 ✓ 1 MA multiplying by coats and no. of shapes1 CA area to be painted1 S simplification1 CA no of litres1 R rounding (5) L3Meas. 3.2.4 0,65 x 1 000 ✓= 650 mℓ ✓Valid ✓ 1 MCA multiplying by 1 0001 CA simplification1 O verification (3) L4Meas. [29]

 QUESTION 4 [19] Ques Solutions Explanations Level 4.1.1 17    x 100 ✓✓ 255= 6,67% ✓ 1A numerator1A denominator1CA percentageNPR        (3) L2Prob 4.1.2 D44  ✓ ✓ 1A letter1A number (2) L1Maps 4.1.3 D = 29 ✓E = 32 ✓H = 41 ✓Total = 29 + 32 +41 = 102 ✓ 3A all rows 1 mark for each row1A correct total           (4) L2Maps 4.2.1 29,9   ✓✓ 2RT correct amount (2) L1Meas 4.2.2 (height)2 x BMI = Weight1,7 x 1,7 x BMI = 95 ✓2,89 x BMI = 95           BMI = 95/2,89 ✓                  = 32,87 ✓Obese / High health risk. Not valid ✓ 1SF substitution1S simplification1CA1O verification  (4) L4Meas 4.2.3 Exercise ✓✓Eat healthy food ✓✓ORAny other relevant answer. 2A 2A2 for each suggestion                                     (4) L4Meas [19] Total:100