Tuesday, 30 August 2022 06:58

## MATHEMATICAL LITERACY PAPER 1 GRADE 12 MEMORANDUM - NSC PAST PAPERS AND MEMOS NOVEMBER 2021

MATHEMATICAL LITERACY PAPER 1
MEMORANDUM
NSC EXAMINATIONS

QUESTION 1 [30 MARKS]
ANSWER ONLY FULL MARKS

1.1.1
\$1,258 - \$0,80
=\$0,458
1MA subtracting different prices
1CA simplification provided 1 value is correct (2)

1.1.2
11,14 Botswana pula = \$1
1 Botswana Pula =   1
11,14
= 0,089767 US dollar
1MA dividing by exchange rate
1A simplification
No penalty for correct rounding (2)

1.1.3
Angola; Namibia or Botswana
1RT first correct country
1RT second correct country
Any two (2)

1.1.4
1,258; 1,061; 0,87; 0,796; 0,732; 0,254
1RT all correct values
1A correct order (2)

1.1.5
0,833
2A correct value (2)

1.2.1
Electricity
2A correct source (2)

1.2.2
Limpopo / LP / Lim / L-Province
2A province (2)

1.2.3

1. Cost of 1 ℓ of paraffin
764,59 100
= R7,6459/ℓ
= R7,65/ℓ
1MA dividing by 100
1A simplification
(2)
2. Cost of paraffin
R7,65/ℓ × 12,5ℓ
= R95,625
= R96,00
CA from Question 1.2.3 (a)
1MCA multiply by 12,5ℓ
1R correct rounding (2)

1.2.4 Solar power OR Coal OR Charcoal OR Wind turbines OR Hydropower OR Generator OR Gel OR Paper OR Straw OR Leaves OR Animal manure (dung) OR Spirits OR Corn stalk
2A correct source
Any one (2)

2A correct instrument (2)

1.3.2 Classifying, preparation, organising, sorting data
2A correct step
Any one word to describe the step (2)

1.3.3 Categorical data
2A correct answer (2)

1.3.4
2A correct answer (2)

1.3.5 Any company who sells books
OR
Publishers
OR
Library
OR
Book Club
OR/OF
Name of a book store
OR
Name of publisher
2A correct answer (2)


QUESTION 2 [32 MARKS]
2.1.1
Hire purchase agreement/HP/Instalment payment/Loan agreement monthly instalment/Credit option/Credit/Balloon payment option/Residual payment option
Huurkoop/HK
2A correct definition
Any one from given list (2)

2.1.2
Ford Figo Deposit
= R215 100 × 5%
= R10 755
1MA multiplying correct values
1A simplification
AO (2)

2.1.3
72 months : 48 months
= 3:2
1RT correct values
1A simplification of 2 correct values
Accept unit ratio
AO (2)

2.1.4
Ford Figo
2A correct vehicle
(2)

2.1.5
R3 345 × 2,08%
= R69,58
Total cost for the VW Polo
= Total monthly instalments + Admin fee + Residual
= (R3 345,00 × 47) + (R69,58 ×47) + R116 759
= R157 215 + R3 270,26 + R116 759
= R277 244,26
1MA calculating 2,08%
1MA multiplying correct values
1MA multiplying correct values
1RT correct value
1CA simplification
(6)

2.1.6
Interest for year 1
R60 000,00 x 4,3
100
= R2 580,00
Amount end of year 1
= R60 000 + R2 580
= R62 580,00
Interest for year 2
62 580,00 x 5,1
100
= R3 191,58
Amount end of year 2
= R62 580,00 + R3 191,58
= R65 771,58
Residual value of Ford Figo
R215 100 × 30%
= R64 530
She is correct
1MA calculating percentage
1A simplification
1MCA calculating percentage
1CA simplification
1M calculating 30%
1CA simplification
1O conclusion.
OR
R60 000,00 x 104,3105,1
100       100

= R65 771,58
Residual value of Ford Figo
R215 100 × 30%
= R64 530
She is CORRECT
1M calculating percentage
1M compound calculation
1CA simplification
1M calculating 30%
1CA simplification
1O conclusion.
(8)

2.2.1
3/Three
2A correct number (2)

2.2.2
ABC made For You S OR made For You S
2A correct device
(2)

2.2.3
VAT calculation
= (R355,65 + R260 + R337,35) × 15%
= R953,00 × 15%
= R142,95
1M adding correct values
1A multiplying by 15%
Accept individual correct calculations: R53,3475 R39,00 R50,60
(2)

2.2.4
A = R355,65 + R260 + R337,35 + R142,95
= R1 095,95
CA from Question 2.2.3
1MA adding correct values
1CA simplification
OR
A = R953 × 1,15
= R1 095,95
1MA multiplying by 1,15
1CA simplification
OR
A = R953 + R142,95
= R1 095,95
1MA adding correct values
1CA simplification
AO (2)

2.2.5
Impossible /Not possible/No chance/Zero percent/Zero/Zero out of three
2A correct term (2)


QUESTION 3 [26 MARKS]
3.1.1
29 March 2021
OR 29/03/2021
1A correct day
1A correct month and year (2)

3.1.2
One hundred and twenty eight million cubic metres
2A number in words
NPU (2)

3.1.3
KwaZulu-Natal OR KZN
2A correct province (2)

3.1.4
Free State/FS
2A Free State
(2)

3.1.5
Mean
83 = D + D + 73 + 82 + 88 + 89 + 99 + 101 + 105
9
83 =  2D + 637
9
2D + 637 = 747
2D = 110
D = 55
1SF substitution mean correctly
1MA dividing by 9
1CA simplification
1MA dividing by 2
1CA simplification
OR
2D + 637 = 83 × 9
2D + 637 = 747
2D = 110
D = 55
1SF substitution mean correctly
1MA multiplying by 9
1CA simplification
1MA dividing by 2
1CA simplification
(5)

3.1.6
Probability
= 1/9
1A numerator
1A denominator (2)

3.1.7
15 657 000 000 x 99/100
= 15 500 430 000
1A correct value in millions
1MA multiplying by %
1CA simplification
Accept 15 500,43 million (3)

3.2.1
Percentage increase
4,3 - 1,7 x 100%
1,7
= 152,94%
1SF correct substitution
1A correct denominator
1CA simplification
NPR (3)
D
L

3.2.2
Save energy (kWh)
OR
Save water (kℓ)
OR/OF
Save money
2A reason (2)

3.2.3
Range of the number of litres/Omvang van die getal liter
120 ℓ – 30 ℓ
= 90 ℓ
Accept litres from 28 – 32
1RT minimum
1RT maximum
1CA simplification
OR
Difference in time
8 min – 2 min
Range = 6 min
6 min × 15 litres/min
= 90 litres
1RT difference in time
1M multiply by 15 min
1CA simplification
NPU (3)


QUESTION 4 [35 MARKS]
4.1.1
Cost of 520 g
520g =  520   x Rs200
1 000
= Rs104
1C conversion
1MA multiplying by correct value
1CA simplification
OR
Unit cost per gram
Rs 200 ÷ 1 000 g
= Rs 0,20/g
Rs 0,20/g × 520 g
= Rs 104
1C conversion
1MA multiplying by correct value
1CA simplification
(3)

4.1.2
Total cost of one plate
(Rs200 + Rs120 + Rs10 + Rs62) ÷ 8
= Rs392
8
= Rs49
Total cost including food container
= Rs49 + Rs2,43
= Rs51,43
1A total ingredients
1MA divide by 8
1CA simplification
1MA adding the container
1CA simplification
OR
Total cost of 8 plates
= Rs200 + Rs120 + Rs10 + Rs62 + (Rs2,43 ×8)
= 392 +(2,43 ×8)
= Rs411,44
Total cost of one plate
= 411,44
8
= Rs51,43
1A total ingredients
1MA adding the container
1CA simplification
1MA divide by 8
1CA simplification
OR
Total cost of one plate
Rs62 + Rs10 + Rs120 + Rs200
8          8            8            8
= Rs25 + Rs15 + Rs1,25 + Rs7,75
= Rs49
Total cost including food container
= Rs49 + Rs2,43
= Rs51,43
1MA divide by 8
1CA simplification
1A total ingredients
1CA simplification
(5)

4.1.3
Profit of one plate
Rs80 – Rs51,43 = Rs28,57
% profit of one plate
= Rs28,57 x 100%
Rs51,43
= 55,55%
Bobby's claim is VALID
CA from Question 4.1.2
1MA subtracting CP from
SP
1CA simplification
1M percentage calculation
1CA simplification
1O conclusion
OR
Rs51,43 × 1,5
=Rs77,15
Rs80,00 > Rs77,15
Bobby's claim is VALID
2A calculating 1,5
1MA multiplying
1CA simplification
1O conclusion
OR
Percentage income
=   Rs80    x 100%
Rs51,43
= 155,55%
Percentage profit
155,55% - 100%
= 55,55%
Bobby's claim is VALID
1MA percentage calculation
1CA simplification
1M subtracting values
1CA simplification
1O conclusion
OR
50% of cost price
= Rs 51,43 x 50%
= Rs 25,72
Profit per plate
= Rs 80 – Rs 51,43
= Rs 28,57
Rs 28,57 >Rs 25,72
Bobby's claim is VALID
1MA percentage calculation
1CA simplification
1M subtracting values
1CA simplification
1O conclusion
(5)

4.1.4
Cost of masala
= Rs10 x 0,206839
Rs1
= R2,06839
= R2,07
1RT correct values
1MA multiplying by 0,260839
1A simplification
OR
Cost of masala
=   Rs10
4,834670
= R2,06839
= R2,07
1RT correct values
1MA dividing
1A simplification
(3)

4.2.1
Cost (R) = 600,00 + 13 p, where p = number of plates.
1 380,00 = 600,00 + 13p
1 380,00 – 600,00 = 13p
R780 = 13 p
p = 60 plates
1SF correct substitution
1MA subtracting 600
1CA simplification
1CA simplification
AO
(4)

4.2.2 1A Start point (0;600)
1A End point (100; 1 900)
1A Correct straight line

 Number of Plates 0 10 30 50 70 90 100 Cost (R) 600 730 990 1250 1510 1770 1900

4.2.3
50 plates
2RT number of plates (2)

4.3.1
= 18,7
100
= 0,187
1CA simplification
AO (2)

4.3.2
As the time increase the number of tourists visiting India increases
2A increases
Accept increase (2)

4.3.3
Number of tourist from Bangladesh
10,93 million x 37,1
100
= 4,05503 million
= 4 055 030
His statement is NOT CORRECT
1RT correct percentage
1M multiply with percentage provided one value is correct
1CA simplification
1O conclusion
OR
Number of tourist from Bangladesh
4,5million    x 100%
10,93 million
= 41,1%
Then 37,1% is less than the 41,1%
His statement is NOT CORRECT
1RT correct values
1M multiply with percentage provided one value is correct
1CA simplification
1O conclusion
(4)

4.3.4
Due to the rounding of large numbers in converting to a percentage
2A stating rounding (2)


QUESTION 5 [27 MARKS]
5.1.1
Tax Bracket 4
OR
Tax Bracket
R423 301 – R555 600
OR
100 263 + 36% of taxable income above 423 300
2A correct tax bracket (2)

5.1.2
Annual tax
R423 301 – R555 600
100 263 + 36% of taxable income above 423 300
R100 263 + 36% (R551 762 R423 300)
R100 263 + (36% × R128 462)
R100 263 + R46 246,32
= R146 509,32
Tax payable
= R146 509,32 R14 220
= R132 289,32
CA from Question 5.1.1
1SF substitution
1CA simplification
1CA tax before rebate
1MCA subtracting rebate
1CA simplification
(5)

5.1.3
Present monthly tax payable
=R132 289,32 ÷ 12
= R11 024,11
Annual tax payable one year older
R132 289,32 – R7 794
= R124 495,32
Monthly tax payable one year older
R124 495,32 ÷ 12
= R10 374,61
Monthly tax savings
R11 024,11 - R10 374,61
= R649,50
His statement is CORRECT
1A correct rebate – R7 794
1MA subtracting rebate and simplification
1CA simplification
1CA simplification
1O conclusion
OR
132 289,32 – R124 495,32
= R7 794
R7 794 ÷ 12
= R649,50
His statement is CORRECT
CA from Question 5.1.2
1MA dividing by 12 and simplify
1RT correct values
2A correct rebate – R7 794
1MA dividing by 12
1CA simplification
1O conclusion
OR
Annual tax payable one year older
= R146 509,32 - R14 220 - R7 794
= R124 495,32
Annual tax payable
= R132 289,32
Monthly tax savings
= R132 289,32 - R124495,32
12
= R649,50
His statement is CORRECT
1MA subtracting rebate and simplification
1A correct tax payable
1M simplification
1MA dividing by 12
1CA simplification
1O conclusion (6)

5.1.4
Medical credits
R310 + R310 + (R209 × 2)
R310 + R310 + R418
= R1 038
1RT correct values
1MA multiplying with 2
1MA adding all the values
1CA simplification
AO (4)

5.2.1

1. Huawei
2RT correct brand
(2)
2. 21,5%
CA from Question 5.2.1 (a)
2RT correct percentage
(2)

5.2.2
IQR = Q3 – Q1
= 18,75 – 15,7
= 3,05
1MA concept of IQR
1RT correct value (Q3)
1RT correct value (Q1)
1CA simplification
(4)

5.2.3
Quartile 3 is at 15,95 which includes 75% of the dataset.
The statement is VALID
OR
15,95% < 16% which is Quartile 3 which includes 75% of the dataset.
The statement is VALID
OR
The 75th percentile is below the 16% on the Box and whisker plot.
The statement is VALID
1O explanation
1O conclusion (2)

TOTAL: 150

Last modified on Thursday, 08 September 2022 08:07