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MATHEMATICAL LITERACY PAPER 2 GRADE 12 MEMORANDUM - 2018 SEPTEMBER PREPARATORY EXAM PAPERS AND MEMOS

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MATHEMATICAL LITERACY PAPER 2
GRADE 12
NATIONAL SENIOR CERTIFICATE
MEMORANDUM
SEPTEMBER 2018

Symbol Explanation
 M Method 
 M/A Method with Accuracy 
 MCA Method with Consistent Accuracy
 CA Consistent Accuracy 
 A Accuracy 
 C Conversion 
 S Simplification 
RT/RG/RM Reading from a table OR Reading from a graph OR Read from map
F Choosing the correct formula
SF Substitution in a formula
J Justification
P Penalty, e.g. for no units, incorrect rounding off etc.
R Rounding Off OR Reason
AO Answer only
NPR No penalty for rounding


QUESTION 1 [39]

Ques. Solution Explanation Level
1.1.1  Municipality = 87 × 5 × 30 ✓
= 13 050 litres ✓
Tank water = 250 – 87
= 163 litres ✓
Tanks = 163 × 5 × 30
= 24 450 litres ✓
Total for municipality and tanks
= 13 050 litres + 24 450 litres
= 37 500 litres ✓
1MA Multiply 5 and 30
1A Number of litres
1CA Litres for tank water
1CA Total litres for the month
1MCA Total litres
(5) 
L3
1.1.2 Litres used from tank = 24 450
No. of kilolitres = 24 450 ÷ 1 000
= 24,45 kℓ ✓
First 6 = 6 × 0
7 to 10 kℓ next 4 = 4 × 7,14
= R28,56 ✓
11 to 15 kℓ = 5 × 12,07
= R60,35 ✓
16 to 20 kℓ = 5 × 17,65
= R88,25 ✓
21 to 30 kℓ = 4,45 × 24,23
= R106,93 ✓
Total amount = R28,56 + R60,35 + R88,25 + R106,93
= R284,09 ✓
Amount with VAT = R284,09 x 1,14 ✓
= R323,86 ✓
Statement is valid ✓
CA from 1.1.1
1C Converting to kilolitres
1MA 2nd Tariff
1MA 3rd Tariff
1MA 4th Tariff
1MA 5th Tariff
1CA Total amount
1M Calculating VAT
1CA VAT incl
1O Valid (9)
L3 and L4
1.1.3 Tank 1:
Volume = πr2h ✓✓
= 3.142 × (105)2 × 142✓
                   2
= 1 229 739,525 ÷ 1 000 ✓
= 1 229,7 ✓
= 1 000 litres ✓
Tank 2:
Volume = πr2h
= 3,142 × (90)2 × 210
= 5 344 542 ÷ 1 000
= 5 344, 542
= 5 000 litres ✓
Total = 1 000 + 5 000
= 6 000 litres ✓
Water needed from tanks = 24 450 litres
Statement invalid. Cannot have enough water if it does not rain.✓
1C mm to cm
1SF Substitution
1MA Finding the radius
1S Simplification
1C Convert to litres
1R Nearest thousand
1CA Rounded to nearest thousand
1CA Total volume for two tanks
1O Not valid (9)
L3
1.2.1 Grade 10 : Grade 11 : Grade 12
Ratio 5 : 3 : 2
Grade 10 = 250 book packs
Total = 5 + 3 + 2
= 10 ✓
510 × total no. of book packs = 250 ✓
0,5 × total number of book packs = 250 ✓
Total number of book packs = 250
                                                0,5 ✓
= 500 book packs ✓
OR
5 = 250
1 = 250 ÷ 5
= 50 ✓
3 = 50 × 3
= 150 ✓
2 = 50 × 2
= 100 ✓
Total = 250 + 150 + 100 ✓
= 500 ✓
1M Adding ratio
1M Concept of ratio
1M Changing subject of formula
1M Dividing
1CA Number of book packs
1MA Unit ratio
1MA Finding value of 3
1MA Finding value of 5
1M Addition
1CA Total book packs (5)
L3
1.2.2 Amount for books packs = R320 × 500
= R160 000 ✓
Amount without VAT = R160 000
                                       1,15 ✓
= R139 130,43 ✓
VAT = R160 000 – R139 130,43 ✓
= R20 869,57 ✓
Amount for 50 = R3 20 × 50
= R16 000 ✓
Statement is valid ✓
CA from 1.2.1
1MCA Cost for book packs
1M Dividing by 1,15
1CA Amount before VAT
1M Subtraction
1CA VAT amount
1MCA Amount of 50 book packs
1O Valid (7)
L4
1.2.3 Probability = 150 + 100
                     500    500
= 250 ✓✓× 100
    500✓
= 50% ✓
CA from 1.2.1
1MCA Adding correct fractions
1CA Numerator
1CA Denominator
1CA Percentage
(4)
L2


Question 2 [43]

Ques. Solution Explanation Level
2.1.1 (a)  Mean 2015
= 59,6 + 76,9 + 75,7 + 68,2 + 97,1 + 77 + 84 + 70,4 +71,4 + 49,1 + 58,6 ✓
= 788
    11 ✓
= 71,64 ✓
1M Adding
1M Dividing by 11
1CA Mean
(3)
L2
2.1.1 (b) Mean 2016
= 69,5 + 75,4 + 73,7 + 65,3 + 97,4 +76,5 + 84 + 70,5 + 71,3 + 57,1 + 52
= 786,7
= 786,7
      11 ✓
= 71,52 ✓
Statement invalid ✓
1MA Adding and dividing
1CA Mean
1O Invalid (3)
L4
2.1.2 2015
49,1; 58,6; 59,6; 68,2; 70,4; 71,4; 75,7; 76,9; 77; 84;
97,1 ✓
Q3 (A) = 77% ✓
IQR = 77 – 59,6
= 17,4% ✓
2016
51,5; 52,0; 65,3; 69,5; 70,5; 71,3; 73,7; 75,4; 76,5; 84,0,97,4
Q1 (B) = 65,3% ✓
IQR = 76,5 – 65,3
= 11,2% ✓
Statement valid ✓
1M Ascending order
1CA Q3 (A)
1CA IQR
1A Q1 (B)
1CA IQR
1O Valid (6)
L4
2.2.1 Annual income = R31 625 × 12
= R379 500 ✓
Tax = 61 910 + 31% of taxable income above 296 540 ✓
= 61 910 + 0,31 × (379 500 – 296 540) ✓
= 61 910 + 0,31 × 82 960 ✓
= 61 910 + 25 717,6
= 87 627,6 – R13 635 ✓
= 73 992 ÷ 12
= 6 166,05 ✓
Grants for 10 children = 380 × 10
= 3 800 ✓
2 old age people = 1 600 × 2
= 3 200 ✓
Total = 3 200 + 3 800
= R7 000 ✓
Statement invalid ✓
1MA Annual income
1RT Correct tax bracket
1SF Substitution
1S Simplification
1M Subtract rebate
1CA Monthly tax
1MA Child grant for 10
1MA Old age grant for 2
1CA Total grants
1O Invalid
(10)
L3 and L4
2.2.2 Amount after first year
= R31 625 × 1,058 ✓
= R33 459, 25 ✓
Amount after second year
= R33 459, 25 × 1,068
= R35 734,48 ✓
Annual salary
= R35 734,48 × 12 ✓
= R428 813,75 ✓
OR
Total annual income
= 31 625 × 12 ✓
= 379 500 ✓ × 1,058 ✓× 1,068 ✓
= R428 813,75 ✓
1M Multiplying by 5,8%
1CA Value for 1st year
1CA Value for 2nd year
1M Multiplying by 12
1CA Annual salary
1M Multiplying by 12
1CA Salary
1CA Value for 1st year
1CA Value for 2nd year
1CA Annual salary (5)
L2
2.3.1 KZN = OAG + CSG
= 669 634 + 2 776 098 ✓
= 3 445 732 ✓
WC = OAG + CSG
= 330 039 + 993 038
= 1 323 077 ✓
Difference = 3 445 732 – 1 323 077
= 2 122 655 ✓
1RT Correct values for KZN
1CA Total
1CA Total
1CA Difference(4)
L2
2.3.2 Northern Cape ✓✓ 2RT Province (2) L2
2.3.3 Gauteng has a greater population ✓✓ 2A Reason (2) L4
2.3.4 FS and NW ✓ remains the same ✓ in 2017 and 2018
The number of the rest of the provinces ✓ decreases ✓
1A Both FS & NW
1A Remains the same
1A Rest of provinces
1A Decrease (4)
L4
2.3.5 2.25 Both bars plotted correctly for
1MA EC
1MA KZN
1MA NC
1MA LP
(4)
L2


Question 3 [31]

Ques. Solution Explanation Level
3.1.1  Measured distance from Cape Town to Durban
= 8,1 cm ✓✓ Accept 7,9 cm to 8,3 cm
Bar Scale
3 cm ✓= 500 km Accept 2,9 cm to 3,1 cm
Actual Distance
= 500 𝑥 8,1
         3 ✓
= 1 350 km ✓
Time taken by first family
= 21:00 – 8:00 – 1,5
= 11,5 hrs ✓
Speed of family = 1 350 𝑘𝑚
                               11,5ℎ𝑟𝑠
= 117,39 km/h ✓
Time taken by second family
= 21:00 – 8,50 – 1,5
= 11 hrs ✓
Speed of family = 1 350 𝑘𝑚
                               11ℎ𝑟𝑠
= 122,72 km/h ✓
Statement is valid ✓
2A Measure distance
1A Measure bar scale
1C Convert distance using bar scale
1CA Distance
1CA Time
1CA Speed
1CA Time
1CA Speed
1O Valid
NPR (10)
 L4
3.1.2 Zambia ✓✓ 2A Country (2) L2
3.2.1 Unknown length (1) = 12 cm – 6 cm
= 6 cm
Unknown length (2) = 10 cm – 2 cm – 4 cm
= 4 cm
Perimeter = 10 + 4 + 4 + 2 + 12 + 6+ 6 + 2 + 6 + 4 ✓✓✓
= 56cm ✓
1M Finding 6 cm
1M Finding 4 cm
1M Adding all values
1CA Perimeter(4)
L2
3.2.2 Area = ℓ × b
Figure 1 = 10 cm × 4 cm
= 40 cm2 ✓
Figure 2 = 4 cm × 6 cm
= 24 cm2 ✓
Figure 3 = 6 cm × 6 cm
= 36 cm2 ✓
Total area = 40 cm + 24 cm +36 cm
= 100 cm2 ✓
Area of page = 28 cm × 20 cm
= 560 cm2 ✓
Area of unshaded part = 560 – 100 ✓
= 460 cm2 ✓
CA from 3.2.1
1MA Calculating area
1MCA Area
1MCA Area
1CA Total area
1CA Area of page
1M Subtraction
1CA Unshaded area (7)
L3
3.3.1 Satara to Olifants = 54km ✓
N’wanetsi to Lower Sabi = 108km ✓
Distance is half; therefore, it can take them half the time to travel.✓✓
1RT Correct distance
1RT Correct distance
2 Explanation (4)
L2 & L4
3.3.2 Punda to Mopani = 130 km
Mopani to Paul Kruger = 220 km ✓
Total = 130 km + 220 km
= 350 km ✓
Skukuza to Pafuri = 380 km
Difference = 380 km – 350 km
= 30 km ✓
Statement valid ✓
1RT Correct values
1MA Adding distances
1CA Difference
1O Valid (4)
L2 & L4


QUESTION 4 [37]

Ques. Solution Explanation Level
4.1.1 Not offered at certain universities ✓✓
OR
No students registered for the course ✓✓
2A Reason(2) L4
4.1.2 Fees for Business at Bond = $33 640
Fees for Engineering at Edith Cowan = $ 25 760 ✓
Total = 33 640 + 25 760
= 59 400 ✓
$1 = R9,68
$59 400 = 9,68 × 59 400 ✓
= R 574 992 ✓
1RT Both values correct
1CA Total
1C Convert to Rand
1CA Amount in Rand (4)
L3
4.1.3 Fees greater than $15 000, but less than $ 30000
= 710 ✓✓
= 0,7 ✓
1A Numerator
1A Denominator
1CA Decimal
(3)
L2
4.2.1 % increase = 38 249−29 678✓✓ × 100 ✓
                            29 678 
= 28,88% ✓
1RT Using correct values
1SF Substitution
1M Multiply by 100
1CA Percentage
NPR (4)
L2
4.2.2 December ✓
People get bonuses in December ✓✓
OR
People budget to spend in December ✓✓✓
1A Month
2R Reason
(3)
L2 & L4
4.2.3 August 2015 – 30 633
August 2016 – 31 556 ✓
Difference = 31 556 – 30 633
= 923 ✓
Amount = 923 × 550 000
= R507 650 000 ✓
14, 81 = 1 Euro
507 650 000 = 1 × 507 650 000
                                  14,81 ✓
= 34 277 515,19 Euro ✓
1RT Both values correct
1MCA Difference
1MCA Amount
1C Convert to €
1CA Amount in €
(5)
L3
4.3.1 Hours worked:
Level 3: Day 1 = 5 hours ✓
Day 2 to 13 = 10 hrs × 12
= 120 ✓
Day 14 = 8 hrs
Total number of hours = 5 + 120 + 8 hours
= 133 hours ✓
Level 2 = 133 hours
Level 1 = 133 – 4 ✓
= 129 hours ✓
Amount for Level 3 = 248 × 133 × 2
= R65 968 ✓
Amount for Level 2 = 133 × 218,24 × 6
= R174 155,52 ✓
Amount for Level 1 = 129 × 163,68 × 32
= R675 671,04 ✓
Total Amount = 65 968 + 174 155,52 + 675 671,04
= R915 794,56 ✓
Statement invalid ✓
1A Hrs for Day 1 1MA Hrs for Day 2 to 13
1CA Total number of hours
1M Subtracting
1CA Calculating hours for Level 1
1MCA Amount Level 3
1MCA Amount Level 2
1MCA Amount Level 1
1CA Total amount
1O Invalid (10)
L4
4.3.2 Distance for 14 days = 14 km × 2 × 14 days ✓
= 392 km ✓
Transport Cost for all employees
= 392 km × 3,18 × 40
= R49 862,40 ✓
Amount as a fraction = 49 862,40
                                    915 794,56 ✓
= 0,05 ✓
Statement is valid ✓
CA from 4.3.1
1MA Return multiply by 14
1CA Total distance
1MCA Transport cost
1M Dividing values
1CA Decimal
1O Valid (6)
L4

TOTAL: 150

Last modified on Tuesday, 14 September 2021 13:08